Bug: Runtime Error

[Bee-Ant]

Here's the code in the following error line:

Code: Select all

CatalogList[i]=(i<82)?i-2:82;

[DST]

lol yes, that's exactly what happened to me with code fuzzy told me about, the whole (x<y)? thing.....

I blame fuzzy. Just...because.

Hear that fuzz!? You are the cause of all my problems in this life!

[Bee-Ant]

I thought it's same thing with % where we can't use the same operand inside the formula, so I changed it to

Code: Select all

ii=i;jj=i-2;
CatalogList[i]=(ii<82)?jj:85;

But didn't help at all...darn

lol yes, that's exactly what happened to me with code fuzzy told me about, the whole (x<y)? thing.....
I blame fuzzy. Just...because.
Hear that fuzz!? You are the cause of all my problems in this life!

That's true...in this case, he's a failed teacher

[DST]

Fuzzy has taught me more than you could know. He is the best teacher i've ever had.

[Bee-Ant]

He treated us differently it seems...
For me, he just suggested me better method to do things. He pushed me to think deeper and then finally I solved the problem myself...
As if he just pushed me to find my own way, lucky you Dee

[Fuzzy]

Code: Select all

CatalogList[i] = (i<82)?i-2:82;

is wrong

try

Code: Select all

CatalogList[i] = (i<82)?(i-2):82;

next time you LISTEN when I teach things.

[Bee-Ant]

Code: Select all

CatalogList[i] = (i<82)?(i-2):82;

next time you LISTEN when I teach things.

Code: Select all

ii=i;jj=i-2;
CatalogList[i]=(ii<82)?jj:85;

See who's not listening here???
Both method should make the same sense...that's why they both didn't work

LISTEN CAREFULLY NOW,

Code: Select all

xxx = (i<82)?i-2:82;

Is NOT wrong

Here's the code that works

Code: Select all

ii=(i<82)?i-2:85;
CatalogList[i]=ii;

The main problem is, we can't put an array into the formula directly

[Fuzzy]

Oh I see. That is strange isnt it?

I tested it with a regular int variable so GE never complained.