random numbers and not repeat??

[futuro]

well, I not know how to use one array, I think tath not dificult... I'm training in this

I need a few numbers (random) but not repeat any numbers, it's posible??

Pleasa help me...

Code: Select all

Array = rand(50);
if ( er... sorry, I'm lost...


[skydereign]

Don't know what you want, this is what I think you are asking; How do you set x values in an array to all random number, but no repeats. Here is one way, not sure it is the best, but it was the only thing to come to mind. Now that I think about it, not sure you should use it. It will work, but I am tired, so I'll get back to you with a better method, unless you don't care.

First is declaring your array, for this x will be 5.

Code: Select all

int randArray[5];

Next will be the setting.

Code: Select all

int i;
int j;
for(i=0;i<5;i++)
{
  randArray[i]=-1;   // this is to prevent 0 from always being last
}

for(i=0;i<5;i++)
{
 repeat:
 randArray=rand(5);
  for(j=0;j<5;j++)
  {
    if(randArray[i]==randArray[j] && i!=j)
    {
      goto repeat;
    }
  }
}

Not very straightforward... I could be wrong in what you want altogether, as you seem to be using Array as a single variable.

[futuro]

Don't know what you want, this is what I think you are asking; How do you set x values in an array to all random number, but no repeats. Here is one way, not sure it is the best, but it was the only thing to come to mind. Now that I think about it, not sure you should use it. It will work, but I am tired, so I'll get back to you with a better method, unless you don't care.

First is declaring your array, for this x will be 5.

Code: Select all

int randArray[5];

Next will be the setting.

Code: Select all

int i;
int j;
for(i=0;i<5;i++)
{
  randArray[i]=-1;   // this is to prevent 0 from always being last
}

for(i=0;i<5;i++)
{
 repeat:
 randArray=rand(5);
  for(j=0;j<5;j++)
  {
    if(randArray[i]==randArray[j] && i!=j)
    {
      goto repeat;
    }
  }
}

Not very straightforward... I could be wrong in what you want altogether, as you seem to be using Array as a single variable.

ok, I work with this, after tell you...

That I need: five rand numbers not repeats.

[futuro]

skydereign, not is that I want,

Code: Select all

   
    int j; int i; 

no problem to declare one or two variables

Code: Select all

for(i=0;i<5;i++)
    {
      randArray[i]=-1;   // this is to prevent 0 from always being last


array not is a random, array is five

Code: Select all

    }

    for(i=0;i<5;i++)

this is a ''for next''?, OK

[skydereign]

That is not the random. The for loop increments, i=0, i<5, i++. So it is going through the array[5]. The random is done for 0 then 1 then 2. The first loop is there to prevent the last number from always being zero. rand picks from 0-4, if rand(5). It checks if all others are not the same as the rand(5), in this case 0, but if they are all zero, then the last will be. Sorry that did not make much sense.

[futuro]

don't worry, this I want:

press 'x' button, and show me one number (rand50), when push 'x' again a new number (rand50) is not repeat with the first.

if I need one array, when I push 'x' button the array contains five numbers not repeat and random.

Don't worry about your scored...

[futuro]

Ok, I think that I got it...

Code: Select all

    int Alea; // Para un numero aleatorio
    int Ce; // Para el for next

    contaor = 0;
    linea30:
    Alea = rand(50);
 
    for (Ce = 0; Ce <5; Ce++)
    {
        if (Elarray[Ce] == Alea) goto linea30;
    }
    Elarray[contaor] = Alea;
    contaor = contaor + 1;
 
    if (contaor <5)
    {
        goto linea30;
    }
 
 

anybody that try if repeat any number?

[rosetaylor01]

Is there a simple way to do this?

I want to pick 5 numbers between 1 and 35 randomly. But I want to make sure there is no chance for the same number showing up.

Correct 4,10,15,24,29

Incorrect 4,4,10,11,11

[skydereign]

It depends on what you consider easy, and how you are using the numbers. You could do this with simple code, or you can do it so it works simply with more complexity. This method is easier to implement. Just put this code into Global Code, then run the randNoRepeat function. The numbers are stored in the array random.

Code: Select all

int random[5];


int
randomGen(int steps)
{
  int i;
  int TRUE = 0;
  int RAND;
  do
  {
    RAND = rand(35);
    for(i=0;i<steps;i++)
    {
      if(RAND!=random[i])
      {
        TRUE=1;
      }
      else
      {
        TRUE=0;
      }
    }
    if(steps==0)
    {
      TRUE=1;
    }
  }
  while(TRUE==0);
 
  return(RAND);
}
 

void
randNoRepeat(void)
{
  int RAND;
  int i;
  for(i=0;i<5;i++)
  {
    RAND = randomGen(i);
    random[i]= RAND;
  }
}