String To Array?

[DilloDude]

I am trying to makke a solution to a problem lots of people have - makeing good conversations. I am trying to write a function that takes a string, and converts it into an array of individual lines. So far, it hasn't worked. So if I have a string which contains "Hello everyone!\nHow are you?\nI am a tree!", it will convert it into an array of strings which contain
[0]:"Hello everyone!"
[1]:"How are you?"
[2]:"I am a tree!"
[3]:""
[4]:""
...
Any suggestions?

[Novice]

I think something like this would work:
read text
use a for statement to scan for "\n"
old position=0;
if it runs in to a "\n" get curent position
copy letters from old position to curent position to array[0]
old position = curent position;
update array by 1
resume search at curent position +1
get next "\n" get new position
copy from old position to new position
...
if EOF is reached break out of the function.

This should work if you have the time and the nerve to get the code right. Hope it helped

[DilloDude]

I can use the strncpy function tto copy n characters across, but how can I specify n characters starting from the xth character?

[DilloDude]

Also, what's the best way to put it in an array? Return it as one or include one as a parameter and set it in the function. And what would be the best the best way to go about it?

[DilloDude]

So how do I create an array of strings in script editor? I can't figure it out.
If I put

Code: Select all

char array[20][200]

I can get it to work if I say

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char ar[20][200]={"Yo Everyone", "How are you?", "I'm Fine"};

but not if I use the function:

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void str_to_array(char *str, char array[20][200])
{
    char string[200];
    char ch2[1];
    int ch;
    int line;
 
    strcpy(string, str);
 
    for (line = 0; line < 20; line ++)
    {
        strcpy(array[line], "");
        for (; ch < 200; ch ++)
        {
            if (string[ch] != '\n')
            {
                ch2[0] = string[ch];
                strcat(array[line], ch2);
            }
        }
    }
}

How can I fix this?

[Novice]

I thik you have to use

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char *array [20][200];

[DilloDude]

No, doesn't work

[makslane]

Try:

void str_to_array(char *str, char **array)

[DilloDude]

It lets me put it in, but when I run it it says there is a problem in line 12:

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strcpy(array[line], "");

it says "READ error in invalid memory area".

[makslane]

If the array size is [20][200],
make sure line < 20 and the resulting string < 200

[DilloDude]

Still doesn't work

[makslane]

Send me the game with subject "String To Array"

[DilloDude]

Sent it.

[makslane]

To avoid the error, you need create the array, not a pointer.
You are using:

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char **arr;

The array point to nothing.
You need use:

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char arr[20][200];

Now, your str_to_array don't solve the problem.
This new code will works:

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void str_to_array(char *str, char array[20][200])
{
   int line = 0;
   char *start = str;

   while(*str)
   {
      if(*str == '\n')
      {
         //End of line found
         //Copy to array
         *str = 0;
         strcpy(array[line], start);
         *str = '\n';

         //Go to next string
         start = str + 1;
         line++;
      }

      str++;
   }

   //Copy last string
   strcpy(array[line], start);
}

[DilloDude]

Thanks a lot!
Now I'm gonna figure out how to talk to someone, and I'm gonna post a tutorial here, because I have seen that some people want to do the same thing.