math question.

[tintran]

if ((score >= 1) && (score <= 5) songnumber = 1;
if ((score >= 6) && (score <= 10) songnumber = 2;
if ((score >= 11) && (score <= 15) songnumber = 3;
and so on...
is there a way to do it without using if? like a math equation maybe?

[Game A Gogo]

songnumber=(int)(score/5)+1;

should work

EDIT:

songnumber=(score)?(int)(score/5)+1:0;

because if score is 0, then songnumber should be zero according to your code O:

[tintran]

thanks Gogo, but if score is 5 songnumber will be int(5/5)+1 which is 2 i want it to be 1.
i know it's probably something really simple, i just can't come up with it right now.
Edit:
I think
songnumber = (int)((score-1)/5) + 1

[Game A Gogo]

yes, that will do! Sorry I didn't came up with the right formula! But yours should do the job perfectly, but it still needs an in-line if statement for it to equal 0 when the score is 0!

songnumber=(score)?(int)((score-1)/5)+1:0;

[tintran]

thanks again.
Now i have tetris partner with multiple songs (by DST)
the only bad thing is it's 63MB instead of 6MB hehe