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Here's the code in the following error line:

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CatalogList[i]=(i<82)?i-2:82;

lol yes, that's exactly what happened to me with code fuzzy told me about, the whole (x<y)? thing.....

I blame fuzzy. Just...because.

Hear that fuzz!? You are the cause of all my problems in this life!

I thought it's same thing with % where we can't use the same operand inside the formula, so I changed it to

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ii=i;jj=i-2;
CatalogList[i]=(ii<82)?jj:85;

But didn't help at all...darn

DST wrote:lol yes, that's exactly what happened to me with code fuzzy told me about, the whole (x<y)? thing.....
I blame fuzzy. Just...because.
Hear that fuzz!? You are the cause of all my problems in this life!

That's true...in this case, he's a failed teacher

Fuzzy has taught me more than you could know. He is the best teacher i've ever had.

He treated us differently it seems...
For me, he just suggested me better method to do things. He pushed me to think deeper and then finally I solved the problem myself...
As if he just pushed me to find my own way, lucky you Dee

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CatalogList[i] = (i<82)?i-2:82;

is wrong

try

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CatalogList[i] = (i<82)?(i-2):82;

next time you LISTEN when I teach things.

Fuzzy wrote:

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CatalogList[i] = (i<82)?(i-2):82;

next time you LISTEN when I teach things.

Bee-Ant wrote:

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ii=i;jj=i-2;
CatalogList[i]=(ii<82)?jj:85;

See who's not listening here???
Both method should make the same sense...that's why they both didn't work

LISTEN CAREFULLY NOW,

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xxx = (i<82)?i-2:82;

Is NOT wrong

Here's the code that works

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ii=(i<82)?i-2:85;
CatalogList[i]=ii;

The main problem is, we can't put an array into the formula directly

Oh I see. That is strange isnt it?

I tested it with a regular int variable so GE never complained.