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Alright so I've never actually arrays and I'm sure there's a LOT better way of doing this. I just need to get 10 x,y locations in an easy to see form like this so i can do things like

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x=pos[0].x;

to put actors where i need them

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Actor pos[9];
And this is what i came up with, pretty bad execution i assume  :lol:
//x position
pos[0].x=15;
pos[1].x=15;
pos[2].x=15;
pos[3].x=15;
pos[4].x=15;
pos[5].x=15;
pos[6].x=15;
pos[7].x=15;
pos[8].x=15;
pos[9].x=15;

//y position
pos[0].y=15;
pos[1].y=15;
pos[2].y=15;
pos[3].y=15;
pos[4].y=15;
pos[5].y=15;
pos[6].y=15;
pos[7].y=15;
pos[8].y=15;
pos[9].y=15;


So can someone teach a guy some arrays, por favor? They seem to be quite useful and if i could just get my foot in the door i feel i could walk myself in

Arrays dont have sub names like that.

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xpos[0] = 15;
xpos[1] = 16;


and so on will work.
usage:

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x = xpos[1];

If the array is formed in global code you can predefine them like so

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int xpos[10] = {15,15,15,15,15,15,15,15,15,15};
int ypos[10] = {1,2,3,4,5,6,7,8,9,10};


or do a 2D array

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int pos[2][10] = {
    {15,15,15,15,15,15,15,15,15,15},
    {1,2,3,4,5,6,7,8,9,10}
};


but I prefer 1D arrays as they are easier to write to disk.

Your other option is to form a structure. You have to do it in global code however. This creates a new variable type.

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typedef struct {
    int x0;
    int x1;
    int x2;
    int x3;
    int x4;
    int x5;
    int x6;
    int x7;
    int x8;
    int x9;
} xfield;


and define a variable like this

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xfield xpos;

and then you can say xpos.x0 = 15;

Its a crappy way to do it if all the fields are the same, so use an array.

Thanks fuzzy, i don't know how you do it but that's the first post i've read about arrays that i actually fully understand!

Fuzzy wrote:Arrays dont have sub names like that.

Well i did make it an Actor so it could use subnames but definately not the best way of doing it

You could make a struct for storing coordinates that just has two values - x and y - and have an array of them. Or just make two separate arrays.